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Ans: C. Due to Snell's law, the fish looks higher than it really is.
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Ans: A.
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Ans: 3.
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Ans: B. One wavelength corresponds to $2\pi$. Quarter wave length difference here.
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Ans: C. Oveall phase difference is what matters.
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Ans: A. $d\sin \theta = m \lambda$. With $d,m$ fixed, bigger $\lambda$ means bigger $\theta$.

Lecture 14: Chapters 34 (Young’s Double Slit) and Section 35-11 (Polarization)

Gone fishing, 1

To shoot a fish with a gun, how should you aim?

Inlined image: fishing_1.png
  1. aim directly at the image
  2. aim slightly above
  3. aim slightly below

Ans: C. Due to Snell's law, the fish looks higher than it really is.

Gone fishing, 2

To shoot a fish with a laser gun, how should you aim?

Inlined image: fishing_2.png
  1. aim directly at the image
  2. aim slightly above
  3. aim slightly below

Ans: A.

Superposition

Inlined image: superposition.png

Ans: 3.

Phase difference

The two waves shown are

Inlined image: phasediff.png
  1. out of phase by $\pi$.

  2. out of phase by $\pi / 2$.

  3. out of phase by $\pi / 4$.

  4. in phase.

Ans: B. One wavelength corresponds to $2\pi$. Quarter wave length difference here.

Young’s double slit experiment

An interference pattern is seen from two slits. Now, cover one slit with glass, introducing a phase difference of $\pi$ (180$^\circ$; half wavelength) at the slits. How is the pattern altered?

Inlined image: double_slit.png
  1. pattern vanishes.
  2. pattern expands.
  3. bright and dark spots are interchanged.
  4. no change at all.

Ans: C. Oveall phase difference is what matters.

Young’s double slit experiment

In a double slit experiment, if the wavelength of the light is increased, the interference pattern will

  1. spread out.
  2. shrinks together.
  3. stays the same.
  4. disappears.

Ans: A. $d\sin \theta = m \lambda$. With $d,m$ fixed, bigger $\lambda$ means bigger $\theta$.