Ph105-11:

Statistics

Here is the histogram for the midterm score distribution. It is a decent distribution. However, I do worry about those students below 110 points or so (according to this plot, there are 23 students below 110) -- please do come and see me if you belong in that group. On the other hand, the exam clearly showed a pretty solid general grasp of core subjects by the majority of students, and I have seen some particularly very nice solutions -- Kudos to you, who did very well!

Inlined image: Histogram.png

Grading Rubrics

Here is the complete grading rubrics used for this midterm. For the problems that you attempted you have gotten one of the percentile grades per each part.

Part 1.p1 (15 points) : Work done by gravity = -mgh
        100 %: practically perfect
         85 %: correct except that the sign is incorrect
         25 %: correct starting formula, but no or little development from it
          0 %: answer missing, or completely incorrect
Part 1.p2 (15 points) : Work done by hand: m(g+a)h/2 + m(g-a)h/2 = mgh
        100 %: practically perfect
         40 %: Used a, for both paths!  (correct ones to use: g+a and g-a)
         25 %: correct starting formula, but no or little development from it
         25 %: correct answer stated with no derivation
          0 %: answer missing, or completely incorrect
Part 1.p3 (10 points) : The net work = -mgh + mgh = 0, confirming the W-E theorem.
        100 %: practically perfect
         95 %: would have been perfect, were it not for (numerical) mistakes accumulated from previous part(s)
         25 %: correct starting formula, but no or little development from it
          0 %: answer missing, or completely incorrect
Part 2.p1 (20 points) : First conservation principle.
        100 %: practically perfect
         67 %: Invariance of L, missing or incorrectly stated
         67 %: the conserved quantity missing or mis-identified (e.g. said L is conserved)
         33 %: conserved quantity OK, but the experimental reproducibility and the L invariance not (or incorrectly) discusssed
         33 %: experimental reproducibility OK, but L invariance and conservation are missing or incorrect
Part 2.p2 (20 points) : Second conservation principle.
        100 %: practically perfect
         67 %: invariance of L, missing or incorrectly stated
         67 %: the conserved quantity missing or mis-identified (e.g. said L is conserved)
         33 %: experimental reproducibility OK, but L invariance and conservation are missing or incorrect
          0 %: answer missing, or completely incorrect
Part 3.p1 (10 points) : EOM: m ddot{x} + k x= mu_k m g
        100 %: practically perfect (or equivalently in the energy view)
         85 %: correct except that the sign is incorrect (or equivalently in the energy view)
         85 %: correct except the spring force incorrectly written as k (x+A)
         33 %: incorrect, using mu_k mg dot{x}
          0 %: answer missing, or completely incorrect
Part 3.p2 (10 points) : General solutions to the EOM
        100 %: practically perfect (or equivalently in the energy view)
         95 %: would have been perfect, were it not for (numerical) mistakes accumulated from previous part(s)
         75 %: x_p good, but x_c is missing an integration constant
         70 %: x_p good, but x_c is not (exponential instead of oscillatory)
         50 %: x_p not correct (missed some factors) and x_c missing an integration constant
         50 %: x_c OK, but x_p incorrect or missing
         40 %: x_c OK except missing an integ constant, and x_p not OK
         33 %: x_c incorrectly obtained, and x_p missing
         33 %: incorrect EOM, and inconsistent solutions for them
         33 %: incorrectly applied the characterstic equation
         33 %: x_c OK except missing an integ const, and x_p missing
          0 %: answer missing, or completely incorrect
Part 3.p3 (10 points) : Correct determination of two constants
        100 %: practically perfect (or equivalently in the energy view)
         95 %: would have been perfect, were it not for (numerical) mistakes accumulated from previous part(s)
         95 %: followed the correct procedure, but symbol A got confused
         75 %: followed the correct procedure, but symbol A confused and did not take the real part of x
         50 %: x_0 satisfied, but not dot{x_0}
         50 %: dot(x_0) satisfied but not x_0
         40 %: some development but with no end results
         25 %: correct starting formula, but no or little development from it
          0 %: answer missing, or completely incorrect
Part 3.p4 (10 points) : Identification of the turning point as dot{x} = 0
        100 %: practically perfect (or equivalently in the energy view)
         33 %: identified as 1/4 period or 3/4 period (incorrect)
          0 %: answer missing, or completely incorrect
Part 3.p5 (10 points) : Turning point value: x = -A + 2 mu_k mg / k
        100 %: practically perfect
         95 %: would have been perfect, were it not for (numerical) mistakes accumulated from previous part(s)
         50 %: time identified correctly, but forgot (?) to give the x value
         50 %: the answer has correct ingredients, but it is incorrect and steps are unclear
          0 %: answer missing, or completely incorrect
Part 4.p1 (10 points) : work-energy theorem:  change in KE = net work
        100 %: practically perfect
         85 %: correct except that the sign is incorrect
          0 %: answer missing, or completely incorrect
Part 4.p2 (10 points) : net work = work done by friction = -km \int dt v^4
        100 %: practically perfect
         85 %: correct except that the sign is incorrect
         50 %: incorrect power of speed
         25 %: did -k m \int dt v^2 instead
          0 %: answer missing, or completely incorrect
Part 4.p3 (10 points) : the 0th order solution for v_x(t), x_y(t) used for the work-by-friction term
        100 %: practically perfect
         75 %: correct except thata = omega t was used (not applicable here)
         50 %: v_y correct, but v_x missing or incorrect
         50 %: v_x correct but v_y is not
          0 %: answer missing, or completely incorrect
Part 4.p4 (10 points) : alpha = kv_0^3 / g (up to other multiplicative constants)
        100 %: practically perfect
         95 %: would have been perfect, were it not for (numerical) mistakes accumulated from previous part(s)
         50 %: close but not quite right (wrong powers of v_0, e.g.)
          0 %: answer missing, or completely incorrect
Part 4.p5 (10 points) : v_f = v_0 (1 - C alpha)
        100 %: practically perfect
         90 %: correct except for a (small) numerical error
         40 %: correct form but incorrect result
         33 %: missing numerical factor(s), leading to inconsistent result, and the final form is not v_0 (1-C alpha)
         25 %: incorrect form (no zero-th order term), incorrect result
         25 %: some computation, but result it not evaluated clearly
          0 %: answer missing, or completely incorrect
Part 5 (50 points) : T = 2 pi sqrt(l/g) for a simple pendulum
        100 %: practically perfect
         95 %: everything good, except I = ml^2 is not used
         90 %: everything good, except a sign error in the EOM
         90 %: everything good, except T  is not obtained (only w0), or is incorrect.
         80 %: everything good (logically at least), except some error in the EOM (dropped l or something similar)
         70 %: everything good, except a major flaw in EOM (extra dot{theta}, e.g.)
         60 %: EOM correct, but solution and T are not
         60 %: slightly incorrect EOM (sign error) and incorrect solution from it, while T = 2pi/w0 is noted
         50 %: incorrect EOM, consistent sols of it, but no T (only w0)
         50 %: incorrect EOM , no/incorrect solution, but T = 2pi/w0 noted
         40 %: slightly incorrect EOM (sign error) and no/little/incorrect development from it
         35 %: incorrect use of energy conservation, which led to a correct answer due to missteps
         33 %: incorrect EOM and inconsistent/non-existent solution from it
         33 %: incorrect use of energy conservation, which led to an incorrect answer
         25 %: answer is stated, but no/little derivation to back it up
         25 %: correct starting formula, but no or little development from it
          0 %: answer missing, or completely incorrect
Part 6.a (15 points) : L = 0.5(m+M)\dot{r}^2 + 0.5 mr^2\dot{theta}^2 - Mgr
        100 %: practically perfect
         85 %: all OK, except two many generalized coords (3 or more)
         85 %: all OK, except a sign mistake in T
         80 %: all OK, except that the kinetic energy of M is missing
         70 %: all OK, except that the kinetic energy of M is missing and too many generalized coords (3 or more)
         70 %: U nearly correct (sign mistake), T nearly correct (# of gen. coord. incorrect), and L = T - U is correct
         70 %: U incorrect, but ok otherwise
         70 %: T incorrect, but ok otherwise
         60 %: T is nearly correct (# of gen. coord. incorrect), U incorrect, and L = T - U is correct
         60 %: U is nearly correct (sign mistake) but T is incorrect, and L = T - U is correct
         33 %: T and U both incorrect but L = T - U is correct
          0 %: answer missing, or completely incorrect
Part 6.b (10 points) : Yes.  No friction, air resistance, etc.  Or, partial L/ partial t = 0 and H = T + U = E.
        100 %: practically perfect
         70 %: said "because there is no friction or any other outside force" (gravity is an outside force)
         60 %: said "because there is nothing doing work on the system" (gravity does work)
         50 %: correct general answer but lacks the discussion of non-conservative forces or the explicit t dep of L
         33 %: correct answer (conserved), but no reason given
          0 %: answer missing, or completely incorrect
Part 6.c (15 points) : p_theta = m r^2 \dot{theta} is conserved
        100 %: practically perfect
         75 %: p_theta is incorrect slightly (incorrect power of theta, e.g.), ok otherwise
         50 %: said that all of p_theta, p_r (or p_z) are conserved.
         50 %: found p_theta, but did not realize/state that it is conserved (or said \dot{theta} is conserved, incorrectly)
         50 %: stated that p_theta is conserved, but it is not/incorrectly found
          0 %: answer missing, or completely incorrect
Part 6.d (10 points) : circular motion with r = sqrt[3]{p_theta^2 / (m M g)}
        100 %: practically perfect
         75 %: ok, except that r is not expressed in terms of p_theta
         75 %: basic set up is good, but minor incorrect step(s) leading to an incorrect answer
         50 %: slightly flawed equation, and did not express the answer in terms of p_theta
         50 %: basic set up OK, but did not use \dot{r} = 0, and got no good answer
         25 %: correct starting formula, but no or little development from it
          0 %: answer missing, or completely incorrect
Part 6.e (10 points) : Yes, try to push or pull and let go -- can prove that it comes back by restoring force!
        100 %: practically perfect
         75 %: correct answer and partially valid argument
         25 %: correct answer stated with no/incorrect derivation
          0 %: answer missing, or completely incorrect
UC Santa Cruz Department of Physics